The probability that two teams would identical halftime scores is on the order of 0.10 (ten percent). The prob. that two teams would have identical endgame scores is lower, say, 0.05 (five percent), due to greater dispersion of scores.

Then the compound prob. is 0.1*0.1*0.05*0.05 = 0.000025, or 25 chances out of one million.

OTOH, there are other potential patterns that could have occurred (equal winning scores, equal point margins), so the odds of something this strange happening are a bit less.

sagegrouse

'Or, at least, that is what I remember from Math 135-136 many decades ago'