Saratoga2
12-13-2014, 08:10 AM
I was musing about basketball and realized I was unsure about the definition used for Offensive Efficiency. My thoughts, which are not a concise definition, are as follows.
Possessions:
Each team has about the same number of possessions per game. These vary depending on pace. Say for an example a team has 70 possessions in a particular game, which of course are opportunities for scoring plays. Turnovers of all types deduct from possessions while offensive rebounding provide additions possessions (shot opportunities). If the team has 15 turnovers and 10 offensive rebounds it would have 65 of 70 opportunites to score in the example above.
Scoring plays:
The players can take two point shots or three point shots. Since the probability of hitting shots is lower for three pointers I see no reason other than to lump them as points per shot taken. Scoring can result at a higher efficiency due to ball movement and assists or just because of the superior talent of players. It still boils down to points per shot taken and by association per shot opportunity.
The other scoring opportunities are from the free throw line. There there can be any of three possibilities:
One point opportunity when fouled on a made basket. The result is either 0 or 1 point.
One and one opportunity (2 potential points). The result is either 0, 1 or 2 points.
Two free throws (2 potential points). The result is either 0, 1 or 2 points.
The efficiency of free throw shooting is the points made out of the potential points. Sorry, if a player misses the front end of a one & one he is 0 for 2 in my book.
My view is that the team had 70 possessions for that particular game and it scored so many points, meaning it scored so many points per possession. Am I being unclear? Is that the way offensive efficiency is calculated?
Possessions:
Each team has about the same number of possessions per game. These vary depending on pace. Say for an example a team has 70 possessions in a particular game, which of course are opportunities for scoring plays. Turnovers of all types deduct from possessions while offensive rebounding provide additions possessions (shot opportunities). If the team has 15 turnovers and 10 offensive rebounds it would have 65 of 70 opportunites to score in the example above.
Scoring plays:
The players can take two point shots or three point shots. Since the probability of hitting shots is lower for three pointers I see no reason other than to lump them as points per shot taken. Scoring can result at a higher efficiency due to ball movement and assists or just because of the superior talent of players. It still boils down to points per shot taken and by association per shot opportunity.
The other scoring opportunities are from the free throw line. There there can be any of three possibilities:
One point opportunity when fouled on a made basket. The result is either 0 or 1 point.
One and one opportunity (2 potential points). The result is either 0, 1 or 2 points.
Two free throws (2 potential points). The result is either 0, 1 or 2 points.
The efficiency of free throw shooting is the points made out of the potential points. Sorry, if a player misses the front end of a one & one he is 0 for 2 in my book.
My view is that the team had 70 possessions for that particular game and it scored so many points, meaning it scored so many points per possession. Am I being unclear? Is that the way offensive efficiency is calculated?